If one root of quadratic
equation
(k+1)x2-5x+2k=0 is reciprocal of
other
than value of k is??
Answer
Let one root of quadratic equation
=α
Then, second root will be 1/α
We have (k+1)x2-5x+2k=0
Sum of zeroes= -b/c and
Product of zeroes= a/c
α×1/α = (k+1)/ 2k
1 = (k+1)/ 2k
2k = (k+1)
K =1
Is this helpful for you the please
Is this helpful for you the please
comment and share it to other.
here it is also some important entrance question (https://grapsvs.blogspot.com/2020/04/0111302223-03333033330222-find-value.html)
here it is also some important entrance question (https://grapsvs.blogspot.com/2020/04/0111302223-03333033330222-find-value.html)
please go on this link to improve your knowledge
thanks for coming.
0 Comments
Please do not enter any spam link in the comment box and please follo me.