hot post

If one root of quadratic equation (k+1)x2-5x+2k=0 is reciprocal of other than value of k is??



*                      If one root of quadratic equation
           (k+1)x2-5x+2k=0 is reciprocal of
            other than value of k is??     


Answer
Let one root of quadratic equation =α
Then, second root will be 1/α
We have (k+1)x2-5x+2k=0
Sum of zeroes= -b/c and
Product of zeroes= a/c
α×1/α = (k+1)/ 2k
1 = (k+1)/ 2k
2k = (k+1)

K =1

Is this helpful for you the please 

comment and share it to other.
here it is also some important entrance question (https://grapsvs.blogspot.com/2020/04/0111302223-03333033330222-find-value.html)

please go on this link to improve your knowledge

thanks for coming.       

Post a Comment

0 Comments